Cmis 102 hands-on lab week 5

Cmis 102 hands-on lab week 5

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CMIS 102 Hands-On Lab
// Week 5
Overview:This hands-on lab allows you to follow and experiment with the critical steps of developing a program including the program description, analysis, test plan, design (using pseudocode visualization), and implementation with C code.  The example provided uses sequential, repetition statements and nested repetition statements.
Program Description:
This program will calculate the average of 3 exams for 5 students. The program will ask the user to enter 5 student names. For each of the students, the program will ask for 3 exam scores.  The average exam score for each student will be calculated and printed.
Analysis:
I will use sequential and repetition programming statements.I will define one String to store student name: StudentName.I will define three Float numbers: Examvalue, Sum, Avg to store exam values the sum of the exams and the average of the exams.The sum will be calculated by this formula: Sum = Sum + ExamvalueFor example, if the first value entered was 80.0 and second was 90.0 and the third exam was 100.0:sum = sum + Examvalue = 0.0 + 80.0sum = 80.0 + 90.0 = 170.0sum = 170.0 + 100.0 = 270.0Avg is then calculated as:Avg = sum/3.0For example 270.0/3.0 = 90.0A nested repetition loop can be used to loop through each of the 5 students and each of the 3 exams:For (students=0; students <5; students++)    For (exams=0;exams<3;exams++)   End ForEnd ForSum values will need to be reset for each student to ensure only one student data is used for calculations each time. 
Test Plan:
To verify this program is working properly the input values could be used for testing:
Test Case
Input
Expected Output
1
Studentname=ChrisExamvalue1=80.0Examvalue2=90.0Examvalue3=100.0Studentname=JohnExamvalue1=70.0Examvalue2=90.0Examvalue3=80.0Studentname=SallyExamvalue1=100.0Examvalue2=100.0Examvalue3=100.0Studentname=PatExamvalue1=50.0Eexamvalue2=70.0Examvalue3=60.0
Studentname=SamExamvalue1=90.0Examvalue2=95.0Examvalue3=100.0 
Average for Chris is 90.0Average for John is 80.0Average for Sally is 100.0
Average for Pat is 60.0Average for Sam is 95.0
Pseudocode:
// This program will calculate the average of 3 exams for 5 students
// Declare variablesDeclare StudentName as StringDeclare ExamValue, Sum, Avg as Float
// Loop through 5 StudentsFor (students=0; students <5 ; students++)   // reset Sum to 0  Set Sum =0.0    Print “Enter Student Name”   Input StudentName   // Nested Loop for Exams  For (exams=0; exams < 3; exams++)      Print “Enter exam grade: n”      Input ExamValue      Set Sum = Sum + ExamValue   End For    Set Avg = Sum/3.0   Print “Average for “ + StudentName + “ is “ + Avg End For 
Flow Chart:
C Code
The following is the C Code that will compile in execute in the online compilers.
// C code
// This program will calculate the average of 3 exams for 5 students.
// Developer: Faculty CMIS102
// Date: Jan 31, 2014
#include <stdio.h>
int main ()
{
  /* variable definition: */
  char StudentName[100];
  float ExamValue, Sum, Avg;
  int students,exams;
   // Loop through 5 Students
  for (students=0; students <5 ; students++)
  {
     // reset Sum to 0
     Sum =0.0; 
     printf(“Enter Student Name n”);
     scanf(“%s”, StudentName);  
     // Nested Loop for Exams
    for (exams=0; exams < 3; exams++)
    {
        printf (“Enter exam grade: n”);
        scanf(“%f”, &ExamValue);
        Sum = Sum + ExamValue;
    }  
    Avg = Sum/3.0;
    printf( “Average for %s is %fn”,StudentName,Avg);
  }
  return 0;
}
Setting up the code and the input parameters in ideone.com:
Note the Student and ExamValues for this run were:John: 90.0 80.0 100.0Jim: 80.0 70.0 90.0Joe: 70.0 100.0 100.0Sally: 100.0 95.0 91.0Sam: 30.0 54.0 68.0You can change these values to any valid integer values to match your test cases.
Results from running the programming at ideone.com:
Learning Exercises for you to try:

What would you change in the design and the code if you wanted to input 10 students and 5 exams?
What is the line of code doing?

      char StudentName[100];
(Hint: We haven’t covered arrays, but a String can be thought of as an array of characters) ?

What would happen if you moved the Set Sum = 0.0 from inside the for loop to right after the declaration. For example:

// Declare variablesDeclare StudentName as StringDeclare ExamValue, Sum, Avg as Float
// Initialize SumSet Sum = 0.0;

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